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1. Electric Charges and Fields
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In the given figure distance of the point from $A$ where the electric field is zero is......$cm$

A
$20$
B
$10$
C
$33$
D
None of these
Solution

(c) Suppose electric field is zero at $N$. Hence $|E_A| = |E_B|$
Which gives ${x_1} = \frac{x}{{\sqrt {\frac{{{Q_2}}}{{{Q_1}}}} + 1}} = \frac{{80}}{{\sqrt {\frac{{20}}{{10}}} + 1}} = 33\,cm$
Standard 12
Physics
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