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12.Atoms
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In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelength in the Balmer series is
A
$5/27$
B
$1/93$
C
$4/9$
D
$3/2$
Solution
(a) In Lyman series ${\lambda _{\max }} = \frac{4}{{3R}}$
In Balmer series ${\lambda _{\max }} = \frac{{36}}{{5R}}.$So required ratio $ = \frac{5}{{27}}$
Standard 12
Physics
