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11.Thermodynamics
normal
In thermodynamic process pressure of a fixed mass of gas is changed in such a manner that the gas releases $30$ joule of heat and $18$ joule of work was done on the gas. If the initial internal energy of the gas was $60$ joule, then, the final internal energy will be ..... $J$
A
$32$
B
$48$
C
$72$
D
$96$
Solution
The change in the internal energy of the system, $U=Q-W$
$Q=-30$
$w=-18$
Hence, $U=-12$ Thus, if the initial internal energy is $60 \mathrm{J}$
the final energy $x$ is given by,
$x-60=-12$
or, $x=48 \mathrm{J}$
Standard 11
Physics