Gujarati
Hindi
11.Thermodynamics
normal

In thermodynamic process pressure of a fixed mass of gas is changed in such a manner that the gas releases $30$ joule of heat and $18$ joule of work was done on the gas. If the initial internal energy of the gas was $60$ joule, then, the final internal energy will be  ..... $J$

A

$32$

B

$48$

C

$72$

D

$96$

Solution

The change in the internal energy of the system, $U=Q-W$

$Q=-30$

$w=-18$

Hence, $U=-12$ Thus, if the initial internal energy is $60 \mathrm{J}$

the final energy $x$ is given by,

$x-60=-12$

or, $x=48 \mathrm{J}$

Standard 11
Physics

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