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4-1.Complex numbers
medium
Let ${z_1},{z_2}$ be two complex numbers such that ${z_1} + {z_2}$ and ${z_1}{z_2}$ both are real, then
A
${z_1} = - {z_2}$
B
${z_1} = {\bar z_2}$
C
${z_1} = - {\bar z_2}$
D
${z_1} = {z_2}$
Solution
(b) Let ${z_1} = a + ib,{z_2} = c + id$, then
${z_1} + {z_2}$ is real ==> $(a + c) + i(b + d)$is real
==> $b + d = 0$ ==> $d = – b$ …..(i)
${z_1}{z_2}$ is real ==> $(ad – bd) + i(ac + bc)$is real
==> $ad + bc = 0$ ==> $a( – b) + bc = 0$==> $a = c$
${z_1} = a + ib = c – id = {\bar z_2}$ $(\because a = c$ and $b = – d)$
Standard 11
Mathematics