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6.Permutation and Combination
hard
Let the number of elements in sets $A$ and $B$ be five and two respectively. Then the number of subsets of $A \times B$ each having at least $3$ and at most $6$ element is :
A
$792$
B
$752$
C
$782$
D
$772$
(JEE MAIN-2023)
Solution
$n ( A \times B )=10$
${ }^{10} C _3+{ }^{10} C _4+{ }^{10} C _5+{ }^{10} C _6=792$
Standard 11
Mathematics