6.Permutation and Combination
hard

Let the number of elements in sets $A$ and $B$ be five and two respectively. Then the number of subsets of $A \times B$ each having at least $3$ and at most $6$ element is :

A

$792$

B

$752$

C

$782$

D

$772$

(JEE MAIN-2023)

Solution

$n ( A \times B )=10$

${ }^{10} C _3+{ }^{10} C _4+{ }^{10} C _5+{ }^{10} C _6=792$

Standard 11
Mathematics

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