Natural length of a spring is 60, cm , and its spring constant is 4000, N/m . A mass of 20, kg is hu

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4-1.Newton's Laws of Motion

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Natural length of a spring is $60\, cm$, and its spring constant is $4000\, N/m$. A mass of $20\, kg$ is hung from it. The extension produced in the spring is,.......$cm$ (Take $g = 9.8\;m/{s^2}$)

A

$4.9$

B

$0.49 $

C

$9.4$

D

$0.94$

Solution

(a)If $x$ is the extension produced in spring.
$F = kx$ $⇒$ $x = \frac{F}{k}$= $\frac{{mg}}{k} = \frac{{20 \times 9.8}}{{4000}} = 4.9\,cm$

Standard 11

Physics

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