On dividing p(x)=x^{3}+2 x^{2}-5 a x-7 by (x+1), remainder is R _{1} and on dividing q(x)=x^{3}+a x^

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On dividing $p(x)=x^{3}+2 x^{2}-5 a x-7$ by $(x+1),$ the remainder is $R _{1}$ and on dividing $q(x)=x^{3}+a x^{2}-12 x+6$ by $(x-2), \quad$ the remainder is $R _{2} .$ If $2 R _{1}+ R _{2}=6,$ then find the value of $a$.

Option A

Option B

Option C

Option D

Solution

$a=2$

Standard 9

Mathematics

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