On dividing $16 x^{2}-24 x+9$ by $4 x-3,$ find the remainder.
$-1$
$0$
$2$
$4$
Find the quotient and the remainder when $x^{3}+x^{2}-10 x+8$ is divided by
$x-1$
Factorise $: 121 x^{2}-289 y^{2}$
Evaluate using suitable identities : $(998)^{3}$
Multiply $x^{2}+4 y^{2}+z^{2}+2 x y+x z-2 y z$ by $(-z+x-2 y)$
By using the factor theorem, show that $(x+2)$ is a factor of the polynomial $6 x^{3}+19 x^{2}+16 x+4$ and then factorise $6 x^{3}+19 x^{2}+16 x+4$
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