On what sum will the compound interest (In ₹) | vedclass

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(c) We have, $6352.50=P\left(1+\frac{10}{100}ight)^{2}\left(1+\frac{\frac{1}{2} 	imes 10}{100}ight)$

$=P\left(\frac{11}{10}ight)^{2}\left(\f

Vedclass · Accepted Answer

$5000$

Vedclass · Answer

(c) We have, $6352.50=P\left(1+\frac{10}{100}ight)^{2}\left(1+\frac{\frac{1}{2} 	imes 10}{100}ight)$

$=P\left(\frac{11}{10}ight)^{2}\left(\frac{21}{20}ight)$

$\Rightarrow P=\frac{6352.50 	imes 10 	imes 10 	imes 20}{11 	imes 11 	imes 21}=₹ 5000$

On what sum will the compound interest (In ₹) for $2 \frac{1}{2}$ years at $10 \%$ amount to ₹ $6352.50 ?$

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