One mole of an ideal gas $\left( {\frac{{{C_p}}}{{{C_v}}} = Y} \right)$ heated by law $P = \alpha V$ where $P$ is pressure of gas, $V$ is volume, $\alpha $ is a constant. What is the molar heat capacity of gas in the process
$C = \frac{R}{{\gamma - 1}}$
$C = \frac{{\gamma R}}{{\gamma - 1}}$
$C = \frac{R}{2}\frac{{\left( {\gamma - 1} \right)}}{{\left( {\gamma + 1} \right)}}$
$C = \frac{R}{2}\frac{{\left( {\gamma + 1} \right)}}{{\left( {\gamma - 1} \right)}}$
Six moles of an ideal gas performs a cycle shown in figure. If the temperature are $T_A = 600\,K,\,\,T_B = 800\,K,\,\,T_C = 2200\,K$ and $T_D = 1200\,K,$ the work done per cycle is...... $kJ$
In an adiabatic expansion of a gas initial and final temperatures are ${T_1}$ and ${T_2}$ respectively, then the change in internal energy of the gas is
An ideal gas heat engine operates in a Carnot cycle between $227\,^oC$ and $127\,^oC$. It absorbs $6\, kcal$ at the higher temperature. The amount of heat (in $kcal$) converted into work is equal to
A monoatomic gas at a pressure $P$, having a volume $V$ expands isothermally to a volume $4V$ and then adibatically to volume $16\, V$. The final pressure of the gas is (Take $\gamma = \frac{3}{2}$)
A motor-car tyre has a pressure of $2\,atm$ at $27\,^oC$. It suddenly bursts. If $\left( {\frac{{{C_p}}}{{{C_v}}} = 1.4} \right)$ for air, find resulting temp