The internal energy of an ideal gas increases during an isothermal process when the gas is 

Two moles of helium gas are taken over the cycle $ABCDA$, as shown in the $P-T$ diagram.The work done on the gas in taking it from $D$ to $A$ is

Thermodynamic processes are indicated in the following diagram. 

Match the following

 $\begin{array}{|l|l|} \hline Column\,\,-\,\,1 & Column\,\,-\,\,2 \\ \hline P\,:\,Process\,\,-\,\,I & \,\,A\,\,:\,\,Adiabatic \\ \hline Q\,:\,Process\,\,-\,\,II & \,\,B\,\,:\,\,Isobaric \\ \hline R\,:\,Process\,\,-\,\,III & \,\,C\,\,:\,\,Isochoric \\ \hline S\,:\,Process\,\,-\,\,IV & \,\,D\,\,:\,\,Isothermal \\ \hline \end{array}$

The figure given below shows the variation in the internal energy $U$ with volume $V$ of $2.0\ mole$ of an ideal gas in a cyclic process $abcda$ . The temperatures of the gas during the processes $ab$ and $cd$ are $500\ K$ and $300\ K$ respectively, the heat absorbed by the gas during the complete process is  …. $J$

(Take $R$ = $8.3\ J/mol-K$ and $ln\ 2$ = $0.69$)

An ideal gas is taken through the cycle $A \to B \to C \to A$ , as shown in the figure. If the net heat supplied to the gas in the cycle is $5\ J$, the work done by the gas in the process $C \to A$ is  …. $J$