One projectile moving with velocity v in space, gets burst into 2 parts of masses in ratio 1 : 3 . s

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4-1.Newton's Laws of Motion

normal

One projectile moving with velocity $v$ in space, gets burst into $2$ parts of masses in the ratio $1 : 3$ . The smaller part becomes stationary. What is the velocity of the other part ?

A$4v$

B$v$

C$\frac {4v}{3}$

D$\frac {3v}{4}$

Solution

$P_{i}=P_{f}$
$\mathrm{m}(\mathrm{V})=\frac{\mathrm{m}}{4}(\mathrm{O})+\frac{3 \mathrm{m}}{4}\left(\mathrm{V}^{1}\right)$
$\Rightarrow \mathrm{V}^{1}=4 \mathrm{V} / 3$

Standard 11

Physics

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One projectile moving with velocity $v$ in space, gets burst into $2$ parts of masses in the ratio $1 : 3$ . The smaller part becomes stationary. What is the velocity of the other part ?

Solution

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