Particle is dropped from the height of $20\,\,m$ from horizontal ground. There is wind blowing due to which horizontal acceleration of the particle becomes $6 ms^{^{-2}}$. Find the horizontal displacement of the particle till it reaches ground.  ........ $m$

  • A

    $6 $

  • B

    $10$

  • C

    $12$

  • D

    $24$

Similar Questions

The horizontal range and maximum height attained by a projectile are $R$ and $H$, respectively. If a constant horizontal acceleration $a=g / 4$ is imparted to the projectile due to wind, then its horizontal range and maximum height will be

The greatest height to which a man can throw a stone is $h$. The greatest distance to which he can throw it, will be

For angles of projection of a projectile at angle $(45^o  +\theta)$ and $(45^o  -\theta ) $ , the horizontal range described by the projectile are in the ratio of 

  • [AIPMT 2006]

A projectile is thrown with a velocity of $10\,m / s$ at an angle of $60^{\circ}$ with horizontal. The interval between the moments when speed is $\sqrt{5 g}\,m / s$ is $..........\,s$ $\left(g=10\,m / s ^2\right)$.

A particle is projected with speed $u$ at angle $\theta$ with horizontal from ground. If it is at same height from ground at time $t_1$ and $t_2$, then its average velocity in time interval $t_1$ to $t_2$ is .........