Position x of a particle at any instant is related with velocity as v = √ {2x + 9} . particle star

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2.Motion in Straight Line

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Position $x$ of a particle at any instant is related with velocity as $v = \sqrt {2x + 9}$ . The particle starts from origin. Then initial acceleration and velocity are

A$1\,\, unit$, $3\,\, unit$

B$2\,\, unit$, $3\,\, unit$

C$4\,\, unit$, $81\,\, unit$

D$9\,\, unit$, $3\,\, unit$

Solution

$v=\sqrt{2 x+9}$
$v^{2}=9+2 x$
Comparing with $v^{2}=v^{2}+2 a x$
$4=3, a=1$

Standard 11

Physics

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