Potential at a point $x$-distance from the centre inside the conducting sphere of radius $R$ and charged with charge $Q$ is
$\frac{Q}{R}$
$\frac{Q}{x}$
$\frac{Q}{{{x^2}}}$
$xQ$
A thin spherical conducting shell of radius $R$ has a charge $q$. Another charge $Q$ is placed at the centre of the shell. The electrostatic potential at a point $p$ at distance $\frac{R}{2}$ from the centre of the shell is
$STATEMENT-1$ For practical purposes, the earth is used as a reference at zero potential in electrical circuits.and
$STATEMENT-2$ The electrical potential of a sphere of radius $R$ with charge $\mathrm{Q}$ uniformly distributed on the surface is given by $\frac{\mathrm{Q}}{4 \pi \varepsilon_0 R}$.
Equal charges are given to two spheres of different radii. The potential will
At the centre of a half ring of radius $R=10 \mathrm{~cm}$ and linear charge density $4 \mathrm{n} \mathrm{C} \mathrm{m}^{-1}$, the potential is $x \pi V$. The value of $x$ is . . . . .
Assertion: Electron move away from a region of higher potential to a region of lower potential.
Reason: An electron has a negative charge.