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2. Electric Potential and Capacitance
easy
Potential at a point $x$-distance from the centre inside the conducting sphere of radius $R$ and charged with charge $Q$ is
A
$\frac{Q}{R}$
B
$\frac{Q}{x}$
C
$\frac{Q}{{{x^2}}}$
D
$xQ$
Solution
(a) Potential at any point inside the charged spherical conductor equals to the potential at the surface of the conductor i.e. $Q/R$.
Standard 12
Physics