Power supplied to a particle of mass 2, kg va | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$P=\frac{3 t^{2}}{2}$

$\mathrm{mv} \frac{\mathrm{dv}}{\mathrm{dt}}=\frac{3 \mathrm{t}^{2}}{2}$

$\frac{V^{2}}{2}=\frac{3 t^{3}}{3 	imes 4}$

$

Vedclass · Accepted Answer

$2$

Vedclass · Answer

$P=\frac{3 t^{2}}{2}$

$\mathrm{mv} \frac{\mathrm{dv}}{\mathrm{dt}}=\frac{3 \mathrm{t}^{2}}{2}$

$\frac{V^{2}}{2}=\frac{3 t^{3}}{3 	imes 4}$

$\frac{V^{2}}{2}=\frac{t^{3}}{4}$

at $t=2$

$\mathrm{V}=2 \mathrm{m} / \mathrm{s}$

Power supplied to a particle of mass $2\, kg$ varies with time as $P = \frac{{3{t^2}}}{2}$ $watt$ . Here, $t$ is in $seconds$ . If velocity of particle at $t = 0$ is $v = 0$, the velocity of particle at time $t = 2\, s$ will be ............ $\mathrm{m}/ \mathrm{s}$

Similar Questions

A sphere of mass $m$ travelling at constant speed $v$ strike another sphere of same mass. If coefficient of restitution is $e$, then ratio of velocity of both spheres just after collision is :-

The work done by a force $\vec F = (-6x^3\hat i)\, N$, in displacing a particle from $x = 4\, m$ to $x = -2\, m$ is .............. $\mathrm{J}$

A body of mass $1\, kg$ is thrown upwards with a velocity $20\, m/s$. It momentarily comes to rest after attaining a height of $18\, m$. How much energy is lost due to air friction ............. $\mathrm{J}$ $(g = 10\, m/s^2)$

Force acting on a particle moving in a straight line varies with the velocity of the particle as $F = \frac{K}{\upsilon }$ where $K$ is a constant. The work done by this force in time $t$ is

Work done in time $t$ on a body of mass $m$ which is accelerated from rest to a speed $v$ in time $t_1$ as a function of time $t$ is given by