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5.Work, Energy, Power and Collision
normal
Power supplied to a particle of mass $2\, kg$ varies with time as $P = \frac{{3{t^2}}}{2}$ $watt$ . Here, $t$ is in $seconds$ . If velocity of particle at $t = 0$ is $v = 0$, the velocity of particle at time $t = 2\, s$ will be ............ $\mathrm{m}/ \mathrm{s}$
A
$1$
B
$4$
C
$2$
D
$2\sqrt 2$
Solution
$P=\frac{3 t^{2}}{2}$
$\mathrm{mv} \frac{\mathrm{dv}}{\mathrm{dt}}=\frac{3 \mathrm{t}^{2}}{2}$
$\frac{V^{2}}{2}=\frac{3 t^{3}}{3 \times 4}$
$\frac{V^{2}}{2}=\frac{t^{3}}{4}$
at $t=2$
$\mathrm{V}=2 \mathrm{m} / \mathrm{s}$
Standard 11
Physics