Pressure inside a soap bubble is greater than the pressure outside by an amount :

(given : $\mathrm{R}=$ Radius of bubble, $\mathrm{S}=$ Surface tension of bubble)

In capillary pressure below the curved surface of water will be

A spherical soap bubble has in ternal pressure $P_0$ and radius $r_0$ and is in equilibrium in an enclosure with pressure ${P_1} = \frac{{8{P_0}}}{9}$ . The enclosure is gradually evacuated . Assuming temperature and surface tension of soap bubble to be fixed find the value of $\frac{{{\rm{final\,\, radius}}}}{{{\rm{initial\,\, radius}}}}$ of soap bubble

A spherical soap bubble of radius $3\,cm$ is formed inside another spherical soap bubble of radius $6\,cm$. If the internal pressure of the smaller bubble of radius $3\,cm$ in the above system is equal to the internal pressure of the another single soap bubble of radius $r\,cm$. The value of $r$ is.......

Excess pressure of one soap bubble is four times more than the other. Then the ratio of volume of first bubble to another one is

In Jager's method, at the time of bursting of the bubble