Raghu invested a certain sum in Scheme X for | vedclass

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Question

(c) Let the sum of money invested by Raghu be $₹ P$.

Then

$\frac{P 	imes 12 	imes 2}{100}+\left\{P\left(1+\frac{20}{100}ight)^{2}-1ight\}=

Vedclass · Accepted Answer

$16200$

Vedclass · Answer

(c) Let the sum of money invested by Raghu be $₹ P$.

Then

$\frac{P 	imes 12 	imes 2}{100}+\left\{P\left(1+\frac{20}{100}ight)^{2}-1ight\}=11016$

or, $\frac{24 P}{100}+P\left\{\left(\frac{6}{5}ight)^{2}-1ight\}=11016$

or $, \frac{24 P}{100}+\frac{11 P}{25}=11016$

or, $\frac{24 P+44 P}{100}=11016$

or, $68 P =11016 	imes 100$

$	herefore P=\frac{11016 	imes 100}{68}=₹ 16200$

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