3. Coordinate Geometry
easy

See Fig., and write the following :

$(i)$ The coordinates of $B$.

$(ii)$ The coordinates of $C$.

$(iii)$ The point identified by the coordinates $(-3, -5)$.

$(iv)$ The point identified by the coordinates $(2, \,- 4)$.

$(v)$ The abscissa of the point $D$.

$(vi)$ The ordinate of the point $H$.

$(vii)$ The coordinates of the point $L$.

$(viii)$ The coordinates of the point $M$.

Option A
Option B
Option C
Option D

Solution

$(i)$ The $x$ – coordinate and the $y$ – coordinate of point $B$ are $-5$ and $2$ respectively. Therefore, the coordinates of point $B$ are $(-\,5,\,2)$.

$(ii)$ The $x$ – coordinate and the $y$ – coordinate of point $C$ are $5$ and $-5$ respectively. Therefore, the coordinates of point $B$ are $(5,\,-5)$.

$(iii)$ The point whose $x$ – coordinate and $y$ – coordinate are $-3$ and $-5$ respectively is point $E$.

$(iv)$ The point whose x-coordinate and $y$ – coordinate are $2$ and $-\,4$ respectively is point $G$.

$(v)$ The $x$ – coordinate of point $D$ is $6$. Therefore, the abscissa of point $D$ is $6$.

$(vi)$ The $y$ – coordinate of point $H$ is $-3$. Therefore, the ordinate of point $H$ is $-3$.

$(vii)$ The $x$ – coordinate and the $y$ – coordinate of point $L$ are $0$ and $5$ respectively. Therefore, the coordinates of point $L$ are $(0, \,5)$.

$(viii)$ The $x$ – coordinate and the $y $- coordinate of point $M$ are $-3$ and $0$ respectively. Therefore, the coordinates of point $M$ is $(-\,3,\, 0)$.

Standard 9
Mathematics

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