Show that points A (1,2), B (-1,-16) and C (0,-7) lie on graph of linear equation y=9 x-7

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4. Linear Equations in Two Variables

easy

Show that the points $A (1,2), B (-1,-16)$ and $C (0,-7)$ lie on the graph of the linear equation $y=9 x-7$

Option A

Option B

Option C

Option D

Solution

For $A (1,2),$ we have $2=9(1)-7=9-7=2$

For $B (-1,-16),$ we have $-16=9(-1)-7=-9-7=-16$

For $C (0,-7),$ we have $-7=9(0)-7=0-7=-7$

We see that the line $y=9 x-7$ is satisfied by the points $A(1,2), B(-1,-16)$ and $C(0,-7).$

Therefore, $A(1,2), B(-1,-16)$ and $C(0,-7)$ are solutions of the linear equation $y=9 x-7$

and therefore, lie on the graph of the linear equation $y=9 x-7$.

Standard 9

Mathematics

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