Shown in diagram is a system of two bodies, a block of mass m and a disc of mass 4 m , held in equil

English

Gujarati

Hindi

4-2.Friction

hard

Shown in the diagram is a system of two bodies, a block of mass $m$ and a disc of mass $4\ m$ , held in equilibrium. If the string $3$ is burnt, find the acceleration of the disc. Neglect the masses of the pulleys $P$ and $Q$ . The co-efficient of friction between the block and horizontal surface is $0.5$ and friction between disc and string is zero ........ $m/s^2$

A

$4$

B

$5$

C

$3$

D

$2$

Solution

$4mg -4T$ = $4ma$ , $T -\mu mg$ = $m (4a)$

Standard 11

Physics

Share

Similar Questions

The coefficient of static friction between two blocks is $0.5$ and the table is smooth. The maximum horizontal force that can be applied to move the blocks together is $\ldots \ldots . N$. (take $\left.g=10\, {ms}^{-2}\right)$

hard

(JEE MAIN-2021)

Initially the whole system is at rest and now a force of $62\ N$ is applied on the block $B$ as shown in the figure. Find the time taken by $'A'$ to fall from the block $'B'$ ……….. $\sec$

hard

Two blocks of masses $m_1$ and $m_2$ are connected with a massless unstretched spring and placed over a plank moving with an acceleration ' $a$ ' as shown in figure. the coefficient of friction between the blocks and platform is $\mu$.

hard

$A$ block of mass $M$ is placed on $a$ horizontal surface and it is tied with an inextensible string to $a$ block of mass, as shown in figure. A block of mass $m_0$ is also placed on $M$ If $\mu < \mu_{min}$ (the minimum friction required to keep the block $m$ stationary), then the downward acceleration of $m$ is

normal

The maximum $"F"$ which will not cause motion of any of the blocks. …… $N$

hard