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6-2.Equilibrium-II (Ionic Equilibrium)
medium
Solubility of $AgCl$ in $0.2\,M\, NaCl$ is $x$ and that in $0.1\, M\, AgNO_3$ is $y$ then which of the following is correct ?
A
$x = y$
B
$x > y$
C
$x < y$
D
we can not predict
Solution
In $0.2\, M\, NaCl ,\left[ Cl ^{-}\right]=0.2$
$\left( K _{ sp }\right)_{ AgCl }=\left[ Ag ^{+}\right]\left[ Cl ^{-}\right]$
$\therefore\left( K _{ sp }\right)_{ AgCl }= x \times 0.2$
$\Rightarrow x =\frac{\left( K _{ sp }\right)_{ AgCl }}{0.2}=5\left( K _{ sp }\right)_{ AgC 1}$
In $0.1\, M\, AgNO 3,\left[ Ag ^{+}\right]=0.1\, M$
$\Rightarrow\left( K _{ sp }\right)_{ AgCl}=0.1 \times y$
$\Rightarrow y =\frac{\left( K _{ sp }\right)_{ AgCl }}{0.1}=10\left( K _{ sp }\right)_{ AgCl}$
$\therefore x\, < \,y$
Standard 11
Chemistry
