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6-2.Equilibrium-II (Ionic Equilibrium)
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Solubility product for salt $A{B_2}$ is $4 \times {10^{ - 12}}$. Calculate solubility
A
$1 \times {10^{ - 3}}\,gm\,\,mol\,/\,litre$
B
$1 \times {10^{ - 5}}\,gm\,\,mol\,/\,litre$
C
$1 \times {10^{ - 4}}\,gm\,\,mol\,/\,litre$
D
$1 \times {10^{ - 2}}\,gm\,\,mol\,/\,litre$
Solution
(c) $A{B_2} \rightleftharpoons \mathop {{A^{2 + }}}\limits_{(S)\,} + \mathop {2{B^ – }}\limits_{{{(2S)}^2}} $
${K_{sp}} = 4{S^3}$
$S = \sqrt[3]{{\frac{{{K_{sp}}}}{4}}} = \sqrt[3]{{\frac{{4 \times {{10}^{ – 12}}}}{4}}}$ $ = 1 \times {10^{ – 4}}\,\,gm.\,mol/litre$
Standard 11
Chemistry
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