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6-2.Equilibrium-II (Ionic Equilibrium)
medium
The $K _{ sp }$ for bismuth sulphide $\left( Bi _{2} S _{3}\right)$ is $1.08 \times 10^{-73}$. The solubility of $Bi _{2} S _{3}$ in $mol \,L ^{-1}$ at $298 \,K$ is ......
A
$1.0 \times 10^{-15}$
B
$2.7 \times 10^{-12}$
C
$3.2 \times 10^{-10}$
D
$4.2 \times 10^{-8}$
(JEE MAIN-2022)
Solution
$Bi _{2} S _{3} \rightleftharpoons 2 Bi ^{3+}+3 S ^{2-}$
$\,\quad\quad\quad\quad2s\quad\quad\quad3s$
$k _{ sp } =(2 s )^{2}(3 s )^{3}$
$=4 s ^{2} \times 27( s )^{3}$
$=108( s )^{5}$
$( s )^{5} =\frac{1.08 \times 10^{-73}}{108}$
$\Rightarrow s =10^{-15}$
Standard 11
Chemistry
