Gujarati
3-2.Motion in Plane
easy

The acceleration of a train travelling with speed of $400 \,m/s$ as it goes round a curve of radius $160\,m$, is

A$1\,\,km/{s^2}$
B$100\,\,\,m/{s^2}$
C$10\,\,m/{s^2}$
D$1\,\,m/{s^2}$

Solution

(a)$a = \frac{{{v^2}}}{r} = \frac{{{{(400)}^2}}}{{160}} = {10^3}\,m/{s^2} = 1\,km/{s^2}$
Standard 11
Physics

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