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4.Average
medium
The average age of $x$ and $y$ is $20$ $years.$ If $z$ were to replace $x,$ the average would be $19$ and if $z$ were to replace $y$, the average would be $21.$ Find the ages of $x, y$ and $z$.
A
$22,18,20$
B
$18,22,20$
C
$22,18,20$
D
$18,20,22$
Solution
Sum of Age of $x$ and $y=40$ $years$
$y$ and $z=38$ $years,$ $Z$ and $X=42$ $years$
$x+y+z=\frac{40+38+42}{2}=\frac{120}{2}=60$
$x=60-38=22$ $years,$ $y=60-42=18$ $years$
$z=60-40=20$ $years$
Standard 13
Quantitative Aptitude
