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4.Average
easy
The average of $50$ numbers is $38 .$ If two numbers $45$ and $55$ are discarded, the average of the remaining set of numbers is
A
$38.5$
B
$37.5$
C
$37.0$
D
$36.5$
Solution
Average of the remaining set of numbers
$=\frac{50 \times 38-(45+55)}{50-2}=\frac{1900-100}{48}=37.5$
Standard 13
Quantitative Aptitude