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4.Average
medium
The average of the squares of of first ten natural numbers is
A
$35.5$
B
$36$
C
$37.5$
D
$38.5$
Solution
The sum of the squares of $n$ Natural numbers
$=\frac{n(n+1)(2 n+1)}{6}$
Average $=\frac{n(n+1)(2 n+1)}{6 \times n}=\frac{(n+1)(2 n+1)}{6}$
Average Square of $10$ Natural number
$=\frac{11 \times 21}{6}=\frac{77}{2}=38.5$
Standard 13
Quantitative Aptitude
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