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The average weight of $3$ men $A, B$ and $C$ is $84 \,k g .$ Another man, $D,$ joins the group, and the average weight becomes $80\, kg .$ If another man, $E$, whose weight is $3 \,kg$ more than that of $D ,$ replaces $A$, then average weight of $B , C , D$ and $E$ becomes $79 \,kg$. The weight of $A$ is (in $kg$)
A
$70$
B
$72$
C
$75$
D
$80$
Solution
Weight of $D=(80 \times 4-84 \times 3) kg =68 \,kg$
Weight of $E=(68+3) Kg =71 \,kg$
$( B + C + D + E )$$'s$ weight $=(79 \times 4) Kg =316 kg$
: $\quad( B + C )$ $'s$ weight $=[316-(68+71)] kg$
Hence, A's weight $=[(84 \times 3)-177] Kg =75 kg$.
Standard 13
Quantitative Aptitude
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