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4.Average
hard
The batting average for $40$ innings of a cricket player is $50$ runs. His highest score exceeds his lowest score by $172$ runs. If these two innings are excluded. the average of the remaining $38$ innings is $48$ runs. The highest score of the player is
A
$165$
B
$170$
C
$172$
D
$174$
Solution
Total Score of the player $=50 \times 40=2000$
$H – L =172$
Total Score excluding Highest \& Lowest $=38 \times 48=$ 1824
$\therefore H + L =2000-1824=176$
By Solving
$H+ L =176$
$H-L=172$
_____________________
$2H=348$
$H =174$
Standard 13
Quantitative Aptitude