Batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest

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The batting average for $40$ innings of a cricket player is $50$ runs. His highest score exceeds his lowest score by $172$ runs. If these two innings are excluded. the average of the remaining $38$ innings is $48$ runs. The highest score of the player is

A

$165$

B

$170$

C

$172$

D

$174$

Solution

Total Score of the player $=50 \times 40=2000$

$H – L =172$

Total Score excluding Highest \& Lowest $=38 \times 48=$ 1824

$\therefore H + L =2000-1824=176$

By Solving

$H+ L =176$

$H-L=172$

_____________________

$2H=348$

$H =174$

Standard 13

Quantitative Aptitude

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