Batting average of a cricket player for 64 innings is 62 runs. His highest score exceeds his lowest

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The batting average of a cricket player for $64$ innings is $62$ runs. His highest score exceeds his lowest score by $180$ runs. Excluding these two innings, the average of remaining innings becomes $60$ runs. His highest score was (in $Runs$)

A

$180$

B

$209$

C

$212$

D

$214$

Solution

Sum of the highest and the lowest score

$H + I =64 \times 62-62 \times 60=62(4)=248$

given, $\quad H – I =180$

$2 H =248+180 \Rightarrow H =214$

Therefore, Highest score $=214$

Standard 13

Quantitative Aptitude

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