Binding energy of electron in a hydrogen atom is 13.6, eV , energy required to remove electron from

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12.Atoms

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The binding energy of the electron in a hydrogen atom is $13.6\, eV$, the energy required to remove the electron from the first excited state of $Li^{++}$ is ......... $eV$

A

$122.4$

B

$30.6$

C

$13.6$

D

$3.4$

Solution

For first excitedstate, $n=2$ and for $Li^{+\,+}\,Z$ $=3$

${{\text{E}}_{\text{n}}} = \frac{{13.6}}{{{{\text{n}}^2}}} \times {{\text{Z}}^2}$ $ = \frac{{13.6}}{4} \times 9 = 30.6{\text{eV}}$

Standard 12

Physics

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