The bob of a pendulum of length $l$ is pulled aside from its equilibrium position through an angle $\theta $ and then released. The bob will then pass through its equilibrium position with speed $v$ , where $v$ equals

  • A

    $\sqrt {2gl\,\sin \,\theta } $

  • B

    $\sqrt {2gl\,\left( {1 - \sin \,\theta } \right)} $

  • C

    $\sqrt {2gl\,\left( {1 - \cos \,\theta } \right)} $

  • D

    $\sqrt {2gl\,\left( {1 + \sin \,\theta } \right)} $

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