Bob of a simple pendulum is of mass 10, gm . It is suspended with a thread of 1, m . If we hold bob

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5.Work, Energy, Power and Collision

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The bob of a simple pendulum is of mass $10\, gm$. It is suspended with a thread of $1\, m$. If we hold the bob so as to stretch the string horizontally and release it. What will be the tension at the lowest position ......... $N$

$1.0$

$0.3$

$0.1$

$0$

Solution

$\mathrm{T}=\mathrm{mg} \cos 0^{\circ}+\frac{\mathrm{mv}^{2}}{\mathrm{r}}=\mathrm{mg} \cos 0^{\circ}+\frac{\mathrm{m}(\sqrt{2 \mathrm{gr}})^{2}}{\mathrm{r}}$

$=3 \mathrm{mg}=0.3 \mathrm{N}$

Standard 11

Physics

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(AIIMS-2001)

The bob of a simple pendulum is of mass $10\, gm$. It is suspended with a thread of $1\, m$. If we hold the bob so as to stretch the string horizontally and release it. What will be the tension at the lowest position ......... $N$

Solution

Similar Questions

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