The bond order in $O_2^ + $ is
$2$
$2.5$
$1.5$
$3$
(b) $B.O.$ $ = \frac{{{N_b} – {N_a}}}{2} = \frac{{10 – 5}}{2} = \frac{5}{2} = 2.5$.
In the conversion of $N_2$ into $N_2^+$ the electron will be lost from which of the following molecular orbital ?
Which has the highest bond energy
The total number of electron that takes part in forming bonds in ${N_2}$ is
Which of the following contains $(2C -1e^-)$ bond
Which of the following species show maximum bond length ?
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