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4.Chemical Bonding and Molecular Structure
easy
The bond order of a molecule is given by
A
The difference between the number of electrons in bonding and antibonding orbitals
B
Total number of electrons in bonding and antibonding orbitals
C
Twice the difference between the number of electrons in bonding and antibonding electrons
D
Half the difference between the number of electrons in bonding and antibonding electrons
Solution
It’s Obvious.
Standard 11
Chemistry
Similar Questions
Match $List-I$ with $List-II$.
| $List-I$ | $List-II$ |
| $(A)$ $\Psi_{ MO }=\Psi_{ A }-\Psi_{ B }$ | $(I)$ Dipole moment |
| $(B)$ $\mu=Q \times I$ | $(II)$ Bonding molecular orbital |
| $(C)$ $\frac{N_{b}-N_{a}}{2}$ | $(III)$ Anti-bonding molecualr orbital |
| $(D)$ $\Psi_{ MO }=\Psi_{ A }+\Psi_{ B }$ | $(IV)$ Bond order |
