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2. Electric Potential and Capacitance
easy
The capacity of a spherical conductor in $ MKS$ system is
A
$\frac{R}{{4\pi {\varepsilon _0}}}$
B
$\frac{{4\pi {\varepsilon _0}}}{R}$
C
$4\pi {\varepsilon _0}R$
D
$4\pi {\varepsilon _0}{R^2}$
Solution
(c) The potential is given as, $V=\frac{q}{4 \pi \varepsilon_{0} R}$
The capacitance is given as, $C=\frac{q}{V}$
$=\frac{q}{\frac{q}{4 \pi \varepsilon_{0} R}}$
$=4 \pi \varepsilon_{0} R$
Thus, the capacity of a spherical conductor is $4 \pi \varepsilon_{0} R$
Standard 12
Physics
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