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2. Electric Potential and Capacitance
easy
The capacity of an air condenser is $2.0\, \,\mu F$. If a medium is placed between its plates. The capacity becomes $ 12\, \,\mu F$. The dielectric constant of the medium will be
A
$5$
B
$4$
C
$3$
D
$6$
Solution
(d) Dielectric constant of medium
$K = \frac{{{\rm{Capacity \,of \,condenser \,with \,medium}}}}{{{\rm{Capacity\, of \,condenser}}}} = \frac{{12}}{{2.0}} = 6$
Standard 12
Physics
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