Chance of throwing a total of 7 or 12 with 2 dice, is

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14.Probability

easy

The chance of throwing a total of $7$ or $12$ with $2$ dice, is

A

$\frac{2}{9}$

B

$\frac{5}{9}$

C

$\frac{5}{{36}}$

D

$\frac{7}{{36}}$

Solution

(d) Total number of outcomes $ = 36$,

For sum $= 7$, favourable outcomes are $6$

$i.e.,$ $(6, 1); (5, 2); (4, 3); (3, 4); (2, 5); (1, 6)$

For sum $= 12$, favourable outcome is only $1$ $i.e.,$ $ (6, 6)$

$\therefore$ Probability $ = \frac{6}{{36}} + \frac{1}{{36}} = \frac{7}{{36}}$.

Standard 11

Mathematics

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