The coefficient of apparent expansion of merc | vedclass

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Question

$\gamma_{\mathrm{real}}=\gamma_{\mathrm{app}}+\gamma_{\mathrm{vessel}}$

So $\left(\gamma_{	ext {app}}, \gamma_{	ext {vessel }}ight)_{	ext {gas

Vedclass · Accepted Answer

$9 	imes 10^{-6}/\,^oC$

Vedclass · Answer

$\gamma_{\mathrm{real}}=\gamma_{\mathrm{app}}+\gamma_{\mathrm{vessel}}$

So $\left(\gamma_{	ext {app}}, \gamma_{	ext {vessel }}ight)_{	ext {gass }}=\left(\gamma_{	ext {app }}+\gamma_{	ext {vessel}}ight)_{steel}$

$\Rightarrow 153 	imes 10^{-6}+\left(Y_{	ext {vessel}}ight)_{	ext {glass }}=\left(144 	imes 10^{-6}+\gamma_{	ext {vessel }}ight)_{	ext {steel }}$

Further. $\left(y_{	ext {vessel}}ight)_{	ext {steel}}=3 a=3 	imes\left(12 	imes 10^{-6}ight)=36 	imes 10^{-6}/^\circ {C}$

$\Rightarrow 153 	imes 10^{-6}+\left(\gamma_{	ext {vessel }}ight)_{	ext {glass}}=144 	imes 10^{-6}+36 	imes 10^{-6}$

$\Rightarrow\left(\gamma_{	ext {vessel }}ight)_{	ext {glass }}=3 \mathrm{a}=27 	imes 10^{-6}/^\circ {C}$

$\Rightarrow a=9 	imes 10^{-6} /^{\circ} \mathrm{C}$

The coefficient of apparent expansion of mercury in a glass vessel is $153\times 10^{-6}/\,^oC$ and in a steel vessel is $144\times 10^{-6}/\,^oC.$ If $\alpha $ for steel is $12 \times 10^{-6}/\,^oC,$ then $\alpha $ that of glass is

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