Coefficient of static friction, {μ ₛ}, between block A of mass 2, kg and table as shown in figure

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4-2.Friction

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The coefficient of static friction, ${\mu _s},$ between block $A$ of mass $2\, kg$ and the table as shown in the figure is $0.2$. ........ $kg$ would be the maximum mass value of block $B$ so that the two blocks do not move. The string and the pulley are assumed to be smooth and massless. $(g = 10\,m/{s^2})$

A$2.0$

B$4.0$

C$0.2$

D$0.4$

(AIPMT-2004)

Solution

(d) ${\mu _s} = \frac{{{m_B}}}{{{m_A}}}$ $⇒$ $0.2 = \frac{{{m_B}}}{2}$ $⇒$ ${m_B} = 0.4\;kg$

Standard 11

Physics

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