The compound interest on ₹ 4000 for 4 years a | vedclass

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Question

(a) $p=4000, n=4, r=10 \%$

$\begin{aligned} C.I &= P \left[1+\frac{ r }{100}ight]^{ n }- P \ &=4000\left[1+\frac{10}{100}ight]^{4}-400

Vedclass · Accepted Answer

$1856.40$

Vedclass · Answer

(a) $p=4000, n=4, r=10 \%$

$\begin{aligned} C.I &= P \left[1+\frac{ r }{100}ight]^{ n }- P \ &=4000\left[1+\frac{10}{100}ight]^{4}-4000 \ &=5856.40-4000 \ C.I &=1856.40 Rs \end{aligned}$

The compound interest on ₹ $4000$ for $4$ years at $10 \%$ per annum will be (In ₹)

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