The correct bond order in the following species is
$O_{2}^+ < O_{2}^- < O_2^{2+}$
$O_{2}^- < O_{2}^+ < O_2^{2+}$
$O_2^{2+} < O_{2}^+ < O_{2}^-$
$O_2^{2+} < O_{2}^- < O_{2}^+$
The correct statement$(s)$ about $O _3$ is (are)
$(A)$ $O$ - $O$ bond lengths are equal.
$(B)$ Thermal decomposition of $O _3$ is endothermic.
$(C)$ $O _3$ is diamagnetic in nature.
$(D)$ $O _3$ has a bent structure.
When $O _2$ is adsorbed on a metallic surface, electron transfer occurs from the metal to $O _2$. The $TRUE$ statement$(s)$ regarding this adsorption is(are)
$(A)$ $O _2$ is physisorbed
$(B)$ heat is released
$(C)$ occupancy of $\pi_{2 p }^*$ of $O _2$ is increased
$(D)$ bond length of $O _2$ is increased
The correct order for $O-O$ bond length in given substance is
$I.$ $H_2O_2$ $II.$ $O_2$ $III.$ $O_3$
The bond order in $NO$ is $2.5$ while that in $N{O^ + }$ is $3.$ Which of the following statements is true for these two species
$AX$ is a covalent diatomic molecule where $A$ and $X$ are second row elements of periodic table. Based on Molecular orbital theory, the bond order of $AX$ is $2.5$. The total number of electrons in $AX$ is ........... (Round off to the Nearest Integer).