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The crystalline form of borax has
($A$) tetranuclear $\left[\mathrm{B}_4 \mathrm{O}_5(\mathrm{OH})_4\right]^{2-}$ unit
($B$) all boron atoms in the same plane
($C$) equal number of $s p^2$ and $s p^3$ hybridized boron atoms
($D$) one terminal hydroxide per boron atom
$C,D$
$A,C$
$A,C,B$
$A,C,D$
Solution
The correct options are
$A$ Tetranuclear $\left[ B _4 O _5( OH )_4\right]^{2-}$ unit
$C$ Equal number of $sp ^2$ and $sp ^3$ hybridized boron atoms
$D$ One terminal hydroxide per boron atom
Correct formula of borax is $Na _2\left[B_4 O _5( OH )_4\right] \cdot 8 H _2 O$.
Borax has tetranuclear. $\left[ B _4 O _5( OH )_4\right]^{2-}$ unit.
Only two $B$ atom lies in the same plane.
Two Boron are $sp ^2 \&$ two are $sp ^3$ hybridised.
One terminal hydroxide is present per boron atom.
Hence, options $A, C$ and $D$ are correct.
