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1.Units, Dimensions and Measurement
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The dimensional formula of permeability of free space $\mu_0$ is
A${A^{ - 2}}{M^1}{L^1}{T^{ - 2}}$
B$ML{T^{ - 2}}$
C$M{L^0}{T^{ - 1}}$
D${A^{ - 1}}ML{T^2}$
(AIIMS-2003) (AIPMT-1991)
Solution
(a) $F = \frac{{{\mu _0}}}{{4\pi }}\,\frac{{2{I_1}{I_2}l}}{r}$ $ \Rightarrow {\mu _0} = [F]\,{[A]^{ – 2}}$ $ = [ML{T^{ – 2}}{A^{ – 2}}]$
Standard 11
Physics
