The dimensions of left(frac{ B ^{2}}{mu_{0}}r | vedclass

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Question

$u =\frac{ B ^{2}}{2 \mu_{0}}$
$u \rightarrow$ Energy per unit volume
$\left[\frac{ B ^{2}}{\mu_{0}}\right]=[ u ]=\frac{\left[ ML ^{2} T ^{-2}\right

Vedclass · Accepted Answer

$\left[ ML ^{-1} T ^{-2}\right]$

Vedclass · Answer

$u =\frac{ B ^{2}}{2 \mu_{0}}$
$u \rightarrow$ Energy per unit volume
$\left[\frac{ B ^{2}}{\mu_{0}}\right]=[ u ]=\frac{\left[ ML ^{2} T ^{-2}\right]}{\left[ L ^{3}\right]}=\left[ ML ^{-1} T ^{-2}\right]$

The dimensions of $\left(\frac{ B ^{2}}{\mu_{0}}\right)$ will be.
(if $\mu_{0}$ : permeability of free space and $B$ : magnetic field)

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The dimensions of $\left(\frac{ B ^{2}}{\mu_{0}}\right)$ will be. (if $\mu_{0}$ : permeability of free space and $B$ : magnetic field)