- Home
- Standard 11
- Physics
2.Motion in Straight Line
medium
The displacement-time graph for two particles $A$ and $B$ are straight lines inclined at angles of ${30^o}$ and ${60^o}$ with the time axis. The ratio of velocities of ${V_A}:{V_B}$ is
A
$1:2$
B
$1:\sqrt 3 $
C
$\sqrt 3 :1$
D
$1:3$
Solution
(d)$\frac{{{v_A}}}{{{v_B}}} = \frac{{\tan {\theta _A}}}{{\tan {\theta _B}}}$ $ = \frac{{\tan 30^\circ }}{{\tan 60^\circ }}$$ = \frac{{1/\sqrt 3 }}{{\sqrt 3 }} = \frac{1}{3}$
Standard 11
Physics
Similar Questions
medium
