Gujarati
Hindi
6-2.Equilibrium-II (Ionic Equilibrium)
hard

The dissociation constant of a substituted benzoic acid at $25^{\circ} \mathrm{C}$ is $1.0 \times 10^{-4}$. The $\mathrm{pH}$ of a $0.01 \ \mathrm{M}$ solution of its sodium salt is

A

$5$

B

$2$

C

$8$

D

$9$

(IIT-2009)

Solution

Sodium salt of benzoic acid is a strong base-weak acid salt and its pH is given as follows:

PH$= \frac{(PKw+pKa+logC)}{2}$ $= \frac{14+4-2}{2}$$=7+2-1=8$ 

Standard 11
Chemistry

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