Distance between plates of a parallel plate capacitor is d . A metal plate of thickness d/2 is place

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2. Electric Potential and Capacitance

easy

The distance between the plates of a parallel plate capacitor is $d$. A metal plate of thickness $d/2$ is placed between the plates. The capacitance would then be

A

Unchanged

B

Halved

C

Zero

D

Doubled

Solution

(d) $C = \frac{{{\varepsilon _0}A}}{{d – (d/2)}} = 2\frac{{{\varepsilon _0}A}}{d}$

Standard 12

Physics

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