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2.Motion in Straight Line
easy
The distance travelled by a particle is related to time $t$ as $x =4 t ^2$. The velocity of the particle at $t =$ $5 s$ is $.........ms^{-1}$
A$40$
B$25$
C$20$
D$8$
(JEE MAIN-2023)
Solution
$x =4 t ^2$
$v =\frac{ dx }{ dt }=8 t$
At $t =5\,sec$
$v =8 \times 5=40\,m / s$
$v =\frac{ dx }{ dt }=8 t$
At $t =5\,sec$
$v =8 \times 5=40\,m / s$
Standard 11
Physics
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